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Chapter 2: Q. 2.34 (page 118)

Find three consecutive integers whose sum is-36.

Short Answer

Expert verified

Three consecutive integers will be-13,-12,-11.

Step by step solution

01

Step 1. Assume three consecutive integers.

Let three consecutive integers are,

1stinteger=n2ndinteger=n+13rdinteger=n+2
02

Step 2. Form the equation.

Question states that, "sum of three consecutive integers is -36".

So the equation will be,

n+(n+1)+(n+2)=-36

03

Step 3. Solve the equation,

Add like terms,

(n+n+n)+(1+2)=-363n+3=-36

04

Step 4. isolate the variable on one side of the equation.

Subtract3from both the sides of the equation,

(3n+3)-3=-36-3

3n=-39

05

Step 5. Divide the equation by3,

3n3=-393

n=-13

06

Step 6. Substitute the value of n.

1stinteger=n=-132ndinteger=n+1=-123rdinteger=n+2=-11

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