91Ó°ÊÓ

We have given that Elliot charges $\$60$to do a job. His monthly expenses are of $\$1,100$.

He wants to earn a profit of at least $\$4,000$.

We have to find hoe many jobs he have to to earn a profit of at least $\$4,000$.

Let he have to do $n$jobs to earn a profit of at least $\$4,000$.

From given information we have :-

$60$times jobs to done minus $\$1,100$is at least $\$4,000$.

From this statement we have the following inequality :-

localid="1644344642355" $60n-1100â‰\yen 4000$

Add $1,100$on both sides of the inequality, then we have :-

$$\begin{gathered} 60n-1100+1100â‰\yen 4000+1100 \\ ⇒60nâ‰\yen 5100 \end{gathered}$$

Divide both sides of the inequality by $60$, then we have :-

$$\begin{gathered} \frac{60n}{60}â‰\yen \frac{5100}{60} \\ ⇒nâ‰\yen 85 \end{gathered}$$

We find that $nâ‰\yen 85$, where $n$is the number of the jobs to do.

Then we can conclude that :-

He must have to do $85$jobs to earn a profit of at least$\$4,000$.