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Rameen’s heating bill is \(5.42per month plus \)1.08per therm. How many therms can Rameen use if he wants his heating bill to be a maximum of $87.50.

Short Answer

Expert verified

Rameen can use maximum 76therms if he wants his heating bill to a maximum of $87.50.

Step by step solution

01

Step 1. Given information

We have given that heating bill is $5.42per month plus $1.08per therm

Rameen wants his heating bill to be maximum at $87.50.

We have find that how many therms he can use so that the maximum heating bill will be $87.50.

02

Step 2. Convert to an inequality

Let he can use ntherms per month so that his heating bill to be maximum at $87.50.

Also we have the heating bill is $5.42per month plus $1.08times used therms.

From this statement we have the following inequality :-

5.42+1.08n≤87.50.

03

Step 3. Solve the inequality

Subtract 5.42from both sides of the inequality, then we have :-

5.42+1.08n-5.42≤87.50-5.42⇒1.08n≤82.08

Now divide both sides by 1.08, then we have :-

1.08n1.08≤82.081.08⇒n≤76

04

Step 4. Final Conclusion

We find that :-

n≤76, where nis the number of used therms.

So we can conclude that :-

He can use maximum 76therms per month if he wants his heating bill to be maximum at $87.50.

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