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91Ó°ÊÓ

In the following exercise, using factorial notation, write the first five terms of the sequence whose general term is given.

an=4n!

Short Answer

Expert verified

The first five terms of the sequence whose general term isan=4n!are4,2,23,16,130.

Step by step solution

01

Step 1. Given information

Thegeneraltermsforthesequenceisgivenasan=4n!Wehavetofindthefirstfivetermsforthesequence

02

Step 2. Calculating the terms

Now,

Weknow,⇒n!=nn−1n−2n−3...

Thus,

localid="1645459062376" n:12345an:a1=41!=41=4a2=42!=42×1=2a3=43!=43×2×1=23a4=44!=44×3×2×1=16a5=45!=45×4×3×2×1=130

03

Step 3. Conclusion

From the above table, we can observe that the first five terms of sequence will be4,2,23,16,130.

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