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91Ó°ÊÓ

In the following exercise, expand each binomial, using the Binomial Theorem.

x-3y5.

Short Answer

Expert verified

The expansion of the given expression by binomial theorem is given as:

(x-3y)5=x5-15x4y+90x3y2-270x2y3+405xy4-243y5

Step by step solution

01

Step 1. Given information   

The given expression isx-3y5

02

Step 2. Expanding the expression  

The binomial expansion of the expression a+bnis given as:

(a+b)n=n0an+n1an-1b1+n2an-2b2+…+nran-rbr+…+nnbn

Similarly, for x-3y5, we have:

a=xb=-3yn=5

Using the binomial expansion, we get:

(x-3y)5=50(x)5+51(x)5-1(-3y)1+52(x)5-2(-3y)2+53(x)5-3(-3y)3+54(x)5-4(-3y)4+55(-3y)5

03

Step 3. Simplifying the expansion   

Simplifying the exponents and evaluating the binomial coefficient, we get:

(x-3y)5=(1)(x)5+(5)(x)4(-3y)1+5!(5-2)!2!(x)39y2+5!(5-3)!3!(x)2-27y3+5!(5-4)!4!(x)181y4+(1)-243y5(x-3y)5=x5-15x4y+90x3y2-270x2y3+405xy4-243y5

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