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Chapter 12: Q 108. (page 1185)

In the following exercises, find the sum of the first 30 terms of each arithmetic sequence.

12, 18, 24, 30, 36, 鈥�

Short Answer

Expert verified

The obtained sum is 2970.

Step by step solution

01

Step 1. Given Information.

The arithmetic sequence is12,18,24,30,36,鈥�.

02

Step 2. Find the common difference d.

Find the common difference of consecutive terms.

d=18鈭�12=6

And, now find the 30th term of the sequence.

a30=12+30鈭�16=12+174=186

03

Step 3. Use the sum formula.

Use the sum formula Sn=n2a1+anto find the sum of the thirtieth term.

S30=30212+186=15198=2970

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Most popular questions from this chapter

Determine if each sequence is geometric. If so indicate the common ratio.

鈸� 鈭�150,鈭�30,鈭�15,鈭�5,-52,0,鈥�

鈸� 5,10,20,40,80,160,鈥�

鈸�8,4,2,1,12,14,鈥�

Write the first five terms of the sequence whose general term isan=3n+4

In the following exercises, expand each binomial using Pascal's Triangle.

(x+y)4

Write the first five terms of the sequence where the first term is 7 and the common difference isd=-4.

In the following exercises, expand each binomial using Pascal's Triangle.

(3x-4)4
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