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Simplify:

a48m7n2100m5n8b54x7y5250x2y23c32a9b7162a3b34.

Short Answer

Expert verified

Part a. After simplifying we get,2m35n3.

Part b. After simplifying we get,3xyx235.

Part c. After simplifying we get,2aba243.

Step by step solution

01

Part a Step 1. Simplify the fraction in the radicand

Given:48m7n2100m5n8

After simplifying the fraction in the radicand we get,

48m7-5n2-8100=12m2n-625=12m225n6

02

Part a Step 2. Use the Quotient property to rewrite the radical as the quotient of two radicals

So, we get12m225n6.

03

Part a Step 3. Simplify the radicals of both the numerator and denominator

After simplifying we get,

12m225n6=2m2·35n32=2m35n3

04

Part b Step 1. Simplify the fraction in the radicand 

Given:54x7y5250x2y23

After simplifying the fraction in the radicand we get,

27x7-2y5-21253=27x5y31253

05

Part b Step 2. Use the Quotient property to rewrite the radical as the quotient of two radicals

So, we get27x5y331253.

06

Part b Step 3. Simplify the radicals of both the numerator and denominator

After simplifying we get,

27x5y331253=3xy33·x23533=3xyx235

07

Part c Step 1. Simplify the fraction in the radicand

Given: 32a9b7162a3b34

After simplifying the fraction in the radicand we get,

16a9-3b7-3814=16a6b5814

08

Part c Step 2. Use the Quotient property to rewrite the radical as the quotient of two radicals

So, we get16a6b44814.

09

Part c Step 3. Simplify the radicals of both the numerator and denominator

After simplifying we get,

16a6b44814=2ab44·a24344=2aba243

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