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Intermediate Algebra

OPENSTAX

$Math Studyset 91影视 Explanations$ Math

OER 2017 Edition 路 1346 pages

ISBN: 9780998625720

Chapter 8: Q. 8.11TI (page 749)

Round to two decimal places:
$(a) \sqrt{11} (b) \sqrt[3]{71} (c) \sqrt[4]{127}$

Short Answer

Expert verified

The solutions of (a), (b) and (c) are $3.32, 4.14 a n d 3.36$ respectively.

Step by step solution

01

Part (a) Step 1. Given information

The root: $\sqrt{11}$

02

Part (a) Step 2. Calculation

We have,

$\sqrt{11} = 3.31662479036 = 3.32 R o u n d t o t w o d e c i m a l p l a c e s$

Therefore, the solution is 2

03

Part (b) Step 1. Given information

The root: $\sqrt[3]{71}$

04

Part (b) Step 2. Calculation

We have,

$\sqrt[3]{71} = 4.14081774942 = 4.14 R o u n d t o t w o d e c i m a l p l a c e s$

Therefore, the solution is $\sqrt[3]{71} 鈮� 4.14$

05

Part (c) Step 1. Given information

The root: $\sqrt[4]{127}$

06

Part (c) Step 2. Calculation

We have,

$\sqrt[4]{127} = 3.3569968229929 = 3.36 R o u n d t o t w o d e c i m a l p l a c e s$

Therefore, the solution is $\sqrt[4]{127} 鈮� 3.36$

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Most popular questions from this chapter

Use the Quotient Property to simplify square roots.

(a) $\frac{\sqrt{72 n^{11}}}{\sqrt{2 n}}$

(b) $\sqrt[3]{\frac{162}{6}}$

(c) $\sqrt[4]{\frac{160 r^{10}}{5 r^{3}}}$

In the following exercises, use the Product Property to simplify radical expression $\sqrt{80} .$

In the following exercises, write with a rational exponent.

$\sqrt[3]{7 c} 鈸� \sqrt[7]{12 d} 鈸� 2 \sqrt[4]{6 b}$

Simplify:

(a) $4^{\frac{3}{2}}$

(b) $27^{- \frac{2}{3}}$

(c) $625^{- \frac{3}{4}}$

In the following exercises, simplify.

(a) $25^{\frac{3}{2}}$

(b) $9^{\frac{- 3}{2}}$

(c) ${(- 64)}^{\frac{2}{3}}$

See all solutions

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