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Intermediate Algebra

OPENSTAX

$Math Studyset 91影视 Explanations$ Math

OER 2017 Edition 路 1346 pages

ISBN: 9780998625720

Chapter 8: Q. 8.113 (page 813)

Solve: $\sqrt{2 r 鈭� 3} + 5 = 0 .$

Short Answer

Expert verified

The equation has no solution.

Step by step solution

01

Step 1 Given equation is,

$\sqrt{2 r 鈭� 3} + 5 = 0 .$

The objective is, we need to find the solution for the given equation.

02

Step 2 To isolate the radical, subtract 5 on both sides.

$\sqrt{2 r 鈭� 3} + 5 - 5 = 0 - 5 \sqrt{2 r 鈭� 3} = - 5$

The equation has no solution. Because, the square root is equal to a negative number.

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Most popular questions from this chapter

Simplify:

a. ${(32 x^{\frac{1}{3}})}^{\frac{3}{5}}$ b. ${(x^{\frac{3}{4}} y^{\frac{1}{2}})}^{\frac{2}{3}}$

Use the Quotient Property to simplify square roots.

(a) $\frac{\sqrt{45 p^{9}}}{\sqrt{5 q^{2}}}$

(b) $\frac{\sqrt[4]{64}}{\sqrt[4]{2}}$

(c) $\frac{\sqrt[5]{128 x^{8}}}{\sqrt[5]{2 x^{2}}}$

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In the following exercises, solve.

$\sqrt{3 y - 4} = - 2$

In the following exercises, solve.
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