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Intermediate Algebra

OPENSTAX

$Math Studyset 91影视 Explanations$ Math

OER 2017 Edition 路 1346 pages

ISBN: 9780998625720

Chapter 8: Q. 8.111 (page 813)

Solve: $\sqrt{3 m + 2} 鈭� 5 = 0 .$

Short Answer

Expert verified

The solution is $m = \frac{23}{3}$ .

Step by step solution

01

Step 1 Given equation is,

$\sqrt{3 m + 2} 鈭� 5 = 0 .$

To isolate the radical add $5$ on both sides.

$\sqrt{3 m + 2} 鈭� 5 + 5 = 5 \sqrt{3 m + 2} = 5$

Now square on both the sides.

$3 m + 2 = {(5)}^{2} 3 m + 2 = 25$

02

Step 2 Now simplify the obtained equation.

$3 m + 2 = 25 3 m = 25 - 2 3 m = 23 m = \frac{23}{3}$

03

Step 3 Let us check the answer.

$\sqrt{3 (\frac{23}{3}) + 2} 鈭� 5 = 0 \sqrt{23 + 2} - 5 = 0 \sqrt{25} - 5 = 0 5 - 5 = 0 0 = 0$

which is true.

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Most popular questions from this chapter

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Explain the difference of finding the $n^{t h}$ root of a number when the index is even compared to when the index is odd.

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