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Intermediate Algebra

OPENSTAX

$Math Studyset 91影视 Explanations$ Math

OER 2017 Edition 路 1346 pages

ISBN: 9780998625720

Chapter 8: Q. 52 (page 756)

What is the difference between $9^{2}$ and $\sqrt{9}$ ?

Short Answer

Expert verified

Squaring a number means multiplying it by itself one and square rooting a number means finding a number whose square is the given number.

$9^{2} = 81 \sqrt{9} = 3$

Step by step solution

01

Step 1. Explanation for squaring a number.

We have $9^{2}$ .

Squaring a number means multiplying it by itself one.

So,

$9^{2} = 9 脳 9 = 81$

02

Step 2. Explanation for square rooting a number.

We have $\sqrt{9}$ .

Square rooting a number means finding a number whose square is the given number.

So,

$\sqrt{9} = \sqrt{3 脳 3} = 3$

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Most popular questions from this chapter

Simplify:

a. $\frac{u^{\frac{4}{5}} 路 u^{\frac{- 2}{5}}}{u^{\frac{- 13}{5}}}$ b. ${(\frac{27 x^{\frac{4}{5}} y^{\frac{1}{6}}}{x^{\frac{1}{5}} y^{\frac{- 5}{6}}})}^{\frac{1}{3}}$

Simplify:

$(a) \sqrt{\frac{75}{48}} (b) \sqrt[3]{\frac{54}{250}} (c) \sqrt[4]{\frac{32}{162}}$

Use the Quotient Property to simplify square roots.

(a) $\sqrt{\frac{75 r^{9}}{s^{8}}}$

(b) $\sqrt[3]{\frac{54 a^{8}}{b^{3}}}$

(c) $\sqrt[4]{\frac{64 c^{5}}{d^{4}}}$

In the following exercises, solve.
$\sqrt{s - 8} = s - 8$

In the following exercises, use the Product Property to simplify radical expressions a. $\sqrt[4]{32}$ ,b. $\sqrt[5]{64}$

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