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Chapter 7: Q.469. (page 741)

The distance to stop a car varies directly with the square of its speed. It takes200feet to stop a car going50mph. How many feet would it take to stop a car going60mph?

Short Answer

Expert verified

The distance will be d=288feet.

Step by step solution

01

Step 1. Given information.

The distancedvaries directly with speed asv2, whend=200feet andv=50mph.

02

Step 2. Write the formula for direct variation.

d=kv2

03

Step 3. Substitute the values and find the value of k.

d=kv2k=dv2k=200502鈥�鈥�d=200,v=50k=2002500k=0.08

04

Step 4. Now find the value of d, when k=0.08 and v=60.

d=kv2d=0.08脳602d=288

05

Step 5. Simplified answer.

Hence, the distance will bed=288 feet.

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