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FindR(x)=f(x)+g(x)wheref(x)=x-4x+3andg(x)=4x+6x2-9.

Short Answer

Expert verified

The resultant expression isx2-3x+18(x-3)(x+3).

Step by step solution

01

Step 1. Given Information

The given functions aref(x)=x-4x+3,g(x)=4x+6x2-9.

02

Step 2. Determine the expression

Substitute the given functions into R(x)=f(x)+g(x).

R(x)=x-4x+3+4x+6x2-9

03

Step 3. Express with common denominator    

  • Factor the denominators of the obtained expression.

x-4x+3+4x+6(x-3)(x+3)

  • The LCD of the terms of obtained expression is (x-3)(x+3).
  • Multiply the numerator and denominator of first term by (x-3).

(x-4)(x-3)(x+3)(x-3)+4x+6(x-3)(x+3)=x2-4x-3x+12(x+3)(x-3)+4x+6(x-3)(x+3)=x2-7x+12(x+3)(x-3)+4x+6(x-3)(x+3)

04

Step 4. Simplify

  • As the denominator is the same for both the terms, perform addition in the numerator and place it over the common denominator.

x2-7x+12+4x+6(x+3)(x-3)=x2-3x+18(x+3)(x-3)

  • So, the resultant expression is x2-3x+18(x+3)(x-3).

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