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Subtract:3b2-4b-5-2b2-6b+5.

Short Answer

Expert verified

The resultant expression is1(b+1)(b-1).

Step by step solution

01

Step 1. Given Information

The given expression is3b2-4b-5-2b2-6b+5.

02

Step 2. Express with common denominator

  • Factor the denominators of the given expression.

3(b-5)(b+1)-2(b-5)(b-1)

  • The LCD of the terms of obtained expression is (b-5)(b+1)(b-1).
  • Multiply the numerator and denominator of first term by (b-1)and second term by (b+1).

role="math" localid="1645088626910" 3(b-1)(b-5)(b+1)(b-1)-2(b+1)(b-5)(b-1)(b+1)=3b-3(b-5)(b+1)(b-1)-2b+2(b-5)(b-1)(b+1)

03

Step 3. Simplify

  • As the denominator is the same for both the terms, subtract the numerator and place it over the common denominator.

3b-3-2b-2(b-5)(b+1)(b-1)=b-5(b-5)(b+1)(b-1)

  • Cancel the common factors from numerator and denominator.

b-5(b-5)(b+1)(b-1)=1(b+1)(b-1)

  • So, the resultant expression is1(b+1)(b-1).

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