Intermediate Algebra

OPENSTAX

$Math Studyset 91影视 Explanations$ Math

OER 2017 Edition 路 1346 pages

ISBN: 9780998625720

Chapter 7: Q 440 (page 737)

In the following exercise solve $\frac{z}{12} + \frac{z + 3}{3 z} = \frac{1}{z}$

Short Answer

Expert verified

The solution is $z = - 4$

Step by step solution

Step 1. Given information

$\frac{z}{12} + \frac{z + 3}{3 z} = \frac{1}{z}$

Step 2. Solve

The least common denominator of all denominators in the equation is $(12) (3 z)$

Clear the fraction by multiplying both sides of the equation by the LCD.

$(12) (3 z) (\frac{z}{12} + \frac{z + 3}{3 z}) = (12) (3 z) (\frac{1}{z}) (12) (3 z) (\frac{z}{12}) + (12) (3 z) (\frac{z + 3}{3 z}) = (12) (3 z) (\frac{1}{z}) 3 z^{2} + 12 (z + 3) = 36 3 z^{2} + 12 z = 0 z + 4 = 0 z = - 4$

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91影视

In the following exercise solve $\frac{z}{12} + \frac{z + 3}{3 z} = \frac{1}{z}$

Short Answer

Step by step solution

Step 1. Given information

Step 2. Solve

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91影视

In the following exercise solvez12+z+33z=1z

Short Answer

Step by step solution

Step 1. Given information

Step 2. Solve

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In the following exercise solve $\frac{z}{12} + \frac{z + 3}{3 z} = \frac{1}{z}$