Intermediate Algebra

OPENSTAX

$Math Studyset 91影视 Explanations$ Math

OER 2017 Edition 路 1346 pages

ISBN: 9780998625720

Chapter 7: Q 437 (page 737)

In the following exercise solve $\frac{1}{b - 2} + \frac{1}{b + 2} = \frac{3}{b^{2} - 4}$

Short Answer

Expert verified

The solution is $b = \frac{3}{2}$

Step by step solution

Step 1. Given Information

$\frac{1}{b - 2} + \frac{1}{b + 2} = \frac{3}{b^{2} - 4}$

Step 2. Solve.

The least common denominator of all denominators in the equation is $(b - 2) (b + 2)$

Clear the fraction by multiplying both sides of the equation by the LCD.

$(b - 2) (b + 2) (\frac{1}{b - 2} + \frac{1}{b + 2}) = (b - 2) (b + 2) (\frac{3}{b^{2} - 4}) ((b - 2) (b + 2) \frac{1}{b - 2} + (b - 2) (b + 2) \frac{1}{b + 2}) = (b - 2) (b + 2) (\frac{3}{b^{2} - 4}) (b + 2) + (b - 2) = 3 2 b = 3 b = \frac{3}{2}$

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91影视

In the following exercise solve $\frac{1}{b - 2} + \frac{1}{b + 2} = \frac{3}{b^{2} - 4}$

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Solve.

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91影视

In the following exercise solve1b-2+1b+2=3b2-4

Short Answer

Step by step solution

Step 1. Given Information

Step 2. Solve.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Math Textbooks

Probability and Statistics

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Study anywhere. Anytime. Across all devices.

In the following exercise solve $\frac{1}{b - 2} + \frac{1}{b + 2} = \frac{3}{b^{2} - 4}$