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Intermediate Algebra

OPENSTAX

$Math Studyset 91影视 Explanations$ Math

OER 2017 Edition 路 1346 pages

ISBN: 9780998625720

Chapter 7: Q. 239 (page 695)

Solve a Rational Equation for a Specific Variable.
In the following exercises, solve.
$a = \frac{b + 3}{c - 2}$ for $c$ .

Short Answer

Expert verified

The solution is $c = \frac{2 a + b + 3}{a}$ .

Step by step solution

01

Step 1. Given

The given rational equation is $a = \frac{b + 3}{c - 2}$ .

02

Step 2. To find

We have to solve the given rational equation for $c$ .

03

Step 3. Calculation

Cross multiply and then solve for $c$ .

$a = \frac{b + 3}{c - 2} a (c - 2) = b + 3 a c - 2 a = b + 3 a c = 2 a + b + 3 c = \frac{2 a + b + 3}{a}$

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Most popular questions from this chapter

In the following exercises, divide the rational expressions.

$\frac{\frac{12 c^{2} - 12}{2 c^{2} - 3 c + 1}}{\frac{4 c + 4}{6 c^{2} - 13 c + 5}}$

For the following exercises, find $R (x) = f (x) . g (x)$ where $f (x) a n d g (x)$ are given.

$f (x) = \frac{4 x}{x^{2} - 3 x - 10} a n d g (x) = \frac{x^{2} - 25}{8 x^{2}}$

Simplify the complex rational expression by writing it as division:

$\frac{1 - \frac{3}{c + 4}}{\frac{1}{c + 4} + \frac{c}{3}}$

Divide $\frac{11 + w}{w - 9} 梅 \frac{121 - w^{2}}{9 - w}$

In the following exercises, solve each rational inequality and write the solution in interval notation.

$\frac{4}{x^{2} - 25} > 0$

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