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Intermediate Algebra

OPENSTAX

$Math Studyset 91影视 Explanations$ Math

OER 2017 Edition 路 1346 pages

ISBN: 9780998625720

Chapter 7: Q. 218 (page 694)

In the following exercises, solve each rational equation.
$\frac{c + 3}{12 c} + \frac{c}{36} = \frac{1}{4 c}$

Short Answer

Expert verified

The solution is $c = - 3$ .

Step by step solution

01

Step 1. Given

The given equation is: $\frac{c + 3}{12 c} + \frac{c}{36} = \frac{1}{4 c}$ .

02

Step 2. To find

We have to solve the equation.

03

Step 3. Calculation

The denominators can never be 0. So, $c 鈮� 0$ .

We multiply both sides by the LCD, then solve the equation.

$\frac{c + 3}{12 c} + \frac{c}{36} = \frac{1}{4 c} \frac{c + 3}{12 c} (36 c) + \frac{c}{36} (36 c) = \frac{1}{4 c} (36 c) (c + 3) (3) + c (c) = 9 3 c + 9 + c^{2} = 9 c^{2} + 3 c = 0 c (c + 3) = 0 c = 0, - 3$

But $c 鈮� 0$ , so $c = - 3$ .

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Most popular questions from this chapter

In the following exercises, find the domain of each function.

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