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Chapter 7: Q. 113 (page 668)

In the following exercises, perform indicated operations.

2yy+3+3y-1

Short Answer

Expert verified

The resultant expression is2y2+y+9(y+3)(y-1).

Step by step solution

01

Step 1. Given Information

The given expression is2yy+3+3y-1.

02

Step 2. Express with common denominator   

  • The LCD of the terms of given expression is (y+3)(y-1).
  • Multiply the numerator and denominator of first term by (y-1)and second term by (y+3).

role="math" localid="1645168052631" 2y(y-1)(y+3)(y-1)+3(y+3)(y-1)(y+3)=2y2-2y(y+3)(y-1)+3y+9(y-1)(y+3)

03

Step 3. Simplify

  • As the denominator is the same for both the terms, perform addition in the numerator and place it over the common denominator.

2y2-2y+3y+9(y+3)(y-1)=2y2+y+9(y+3)(y-1)

  • So, the resultant expression is 2y2+y+9(y+3)(y-1).

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