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Intermediate Algebra

OPENSTAX

$Math Studyset 91影视 Explanations$ Math

OER 2017 Edition 路 1346 pages

ISBN: 9780998625720

Chapter 7: Q. 1 (page 651)

In the following exercises, determine the values for which the rational expression is defined.
$(a) \frac{2 x^{2}}{z} (b) \frac{4 p - 1}{6 p - 5} (c) \frac{n - 3}{n^{2} + 2 n - 8}$

Short Answer

Expert verified

$(a) \frac{2 x^{2}}{z} isundefinedat z = 0 (b) \frac{4 p - 1}{6 p - 5} isundefinedat p = \frac{5}{6} (c) \frac{n - 3}{n^{2} + 2 n - 8} isundefinedat n = - 4, 2$

Step by step solution

01

Step 1. Given information

$(a) \frac{2 x^{2}}{z} (b) \frac{4 p - 1}{6 p - 5} (c) \frac{n - 3}{n^{2} + 2 n - 8}$

02

Part a.step 1.find the undefined values

$(a) \frac{2 x^{2}}{z}$

Equate the denominator to zero and solve for the unknown variable.

$z = 0$

Hence, the undefined value at $z = 0 .$

03

Part b.step 1.find the undefined values

$(b) \frac{4 p - 1}{6 p - 5}$

Equate the denominator to zero and solve for the unknown variable.

$6 p - 5 = 0 6 p = 5 p = \frac{5}{6}$

Hence, the undefined value at $p = \frac{5}{6} .$

04

Part c.step 1.find the undefined values

$(c) \frac{n - 3}{n^{2} + 2 n - 8}$

Equate the denominator to zero and solve for the unknown variable.

$n^{2} + 2 n - 8 = 0 (n + 4) (n - 2) = 0 n + 4 = 0 鈬� n = - 4 n - 2 = 0 鈬� n = 2$

Hence, the undefined values are at $n = - 4, 2 .$

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Most popular questions from this chapter

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