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Chapter 9: TRY IT : : 9.92 (page 931)

Find the intercepts of the parabola whose function is f(x)=x2鈭�4x鈭�5.

Short Answer

Expert verified
  • The y-intercept at the point (0, -5)
  • The x-intercepts at the points (5, 0) and (鈭�1, 0) .

Step by step solution

01

Step 1. To find the y-intercept, let x = 0 andsolve for f (x) .

f(x)=x2鈭�4x鈭�5f(0)=(0)2鈭�4(0)鈭�5f(x)=鈭�5

When x = 0 , then f (0) = -5 .

The y-intercept at the point (0, -5) .

02

Step 2. To find the x-intercept, let f (x) = 0 andsolve for x .

f(x)=x2鈭�4x鈭�50=x2鈭�4x鈭�5

Solve by factoring.

localid="1646062204697" 0=(x-5)(x+1)0=x-5;0=x+15=x;-1=x

When f (x) = 0 , then x = 5 or x = 鈭�4 .

The x-intercepts are the points (5, 0) and (鈭�1, 0) .

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