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Solve(3r+4)2=-8

Short Answer

Expert verified

The solutions arer=-43+i223,r=-43-i223

Step by step solution

01

Step 1. Given information

Consider the quadratic equation(3r+4)2=-8

Use the Square Root Property and simplify the radical.

Ifx2=k, thenx=±k

(3r+4)=±-8(3r+4)=±8i(3r+4)=±4·2i(3r+4)=±22i

Subtract 4 from both sides.

3r=±22i-4

Divide both sides by 3.

r=±22i-43

Rewrite in standard form.

r=±223i-43

Rewrite to show two solutions.

localid="1645459017698" r=223i-43,r=-223i-43

02

Step 2. Check for solutions.

Substitute r=223i-43in the original equation.

(3r+4)2=-83223i-43+42=?-8-22-4+42=?-8-4·2=?-8-8=-8

Substituter=-223i-43in the original equation.

(3r+4)2=-83-223i-43+42=?-8-22-4+42=?-8-4·2=?-8-8=-8

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