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Chapter 9: Q. 9.89 (page 930)

Find the intercepts of the parabola whose function is f(x)=x2+2x鈭�8.

Short Answer

Expert verified
  • The y-intercept is the point (0, 鈭�8) .
  • The x-intercepts are the points(鈭�4,0)and(2,0)

Step by step solution

01

Step 1. Given Information

The parabola whose function is f(x)=x2+2x-8

We have to find the intercepts of the parabola.

02

Step 2. Solve

To find the y-intercept, let x = 0 and solve for f (x) .

f(x)=x2+2x鈭�8f(0)=(0)2+2(0)鈭�8f(0)=鈭�8

When x = 0 , then f (0) = 鈭�8 .

The y-intercept is the point (0, 鈭�8) .

To find the x-intercept, let f (x) = 0 and solve for x .

localid="1646151346632" f(x)=x2+2x鈭�80=x2+2x鈭�8

Solve by factoring:

0=x2+2x鈭�80=(x+4)(x-2)0=x+4;0=x-2-4=x;2=x

When f(x)=0, then x=-4orx=2.

The x-intercepts are the points(-4,0)and(2,0)

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