91影视

鈸� $x^2+3x+3<0$ 鈸�$x^2+3x+3>0$

Write the quadratic inequality in standard form.

$x^2+3x+3<0$

Determine the critical points by solving the related quadratic equation.

$x^2+3x+3=0$

Write the Quadratic Formula., and simplify the radicand

$$\begin{gathered} x=\frac{-b卤\sqrt{b^2-4ac}}{2a} \\ x=\frac{-3卤\sqrt{-3}}{2} \end{gathered}$$

The complex solutions tell us the parabola does not intercept the x-axis.

Also, the parabola opens upward. This tells us that the parabola is completely above the x-axis.

Write the quadratic inequality in standard form.

$x^2+3x+3>0$

Determine the critical points by solving the related quadratic equation

$x^2+3x+3=0$

Since the corresponding quadratic equation is the same as in part (a), the parabola will be the same.

The parabola opens upward and is completely above the x-axis鈥攏o part of it is below the x-axis.

We are to find the solution to $x^2+3x+3>0$The solution of the inequality in the interval notation is$鈥�\left(-鈭�鈥�,鈥�鈭�鈥�\right)$.