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Intermediate Algebra

OPENSTAX

$Math Studyset 91影视 Explanations$ Math

OER 2017 Edition 路 1346 pages

ISBN: 9780998625720

Chapter 9: Q 33. (page 869)

Solve quadratic equation $4 {(x + 3)}^{2} - 5 = 27$ using square root property

Short Answer

Expert verified

The values of $x$ are $- 3 - 2 \sqrt{2}$ and $- 3 + 2 \sqrt{2}$

Step by step solution

01

Step 1. Given information

The quadratic equation $4 {(x + 3)}^{2} - 5 = 27$

$鈬� 4 {(x + 3)}^{2} = 32$

$鈬� {(x + 3)}^{2} = 8$

02

Step 2. Use square root property

$鈬� x + 3 = 卤 2 \sqrt{2}$

$鈬� x = - 3 卤 2 \sqrt{2}$

$鈬� x = - 3 + 2 \sqrt{2}$ and $x = - 3 - 2 \sqrt{2}$

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