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Chapter 9: Q. 252 (page 944)

In the following exercises, find the intercepts of the parabola whose function is given.

f(x)=4x2+4x+1

Short Answer

Expert verified

The x-intercept is -12,0and they-intercept is (0,1).

Step by step solution

01

Step 1. Given and explanation   

We are given a function,

f(x)=4x2+4x+1

The y intercept is given by putting x=0 and the x intercept is given by putting the function equals to zero.

02

Step 2. Finding y- intercept  

Putting x=0in the given function, we get

f(0)=4(0)2+4(0)+1f(0)=1

Hence they-intercept is (0,1).

03

Step 3. Finding x- intercept  

Putting f(x)=0, we get

f(x)=04x2+4x+1=04x2+2x+2x+1=0(2x+1)(2x+1)=02x+1=0x=-12

or

2x+1=0x=-12

Hence the x-intercept is at the points (-12,0).

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