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Chapter 9: Q. 227E (page 920)

Make up a problem involving the product of two consecutive odd integers.

鈸� Start by choosing two consecutive odd integers. What are your integers?

鈸� What is the product of your integers?

鈸� Solve the equation n(n + 2) = p, where p is the product you found in part (b).

鈸� Did you get the numbers you started with?

Short Answer

Expert verified
  • 鈸� 3 and 5 are our chosen integers.
  • 鈸� 15 is the product of our chosen integers
  • 鈸� Solution of equation n(n+2)=15is n=-5andn=3
  • 鈸� No, We don't get the numbers we started with.

Step by step solution

01

Part (a) Step 1. Solution of 鈸�  

We have to choose two consecutive odd integers.

So we choose 3 and 5

02

Part (b) Step 1. Solution of 鈸� 

We want to know what is the product of our chosen integers.

So we have3脳5=15

03

Part (c) Step 1. Solution of 鈸�

Now we have to Solve the equation n(n+2)=p, where p is the

product we found in step 2.

So equation become n(n+2)=15

We have to solve it.

n(n+2)=15n2+2n-15=0(n+5)(n-3)=0n+5=0;n-3=0n=-5;n=3

04

Part (d) Step 1. Solution of 鈸�

We want to know Did we get the numbers we started with.

We observe that we get n=-5andn=3

But we started with 3and5.

Therefore, We don't get the numbers we started with.

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Most popular questions from this chapter

Solve :- (y-4)2+8(y-4)+15=0

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