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Chapter 9: Q. 165 (page 906)

In the following exercises, solve. (3y+2)2+(3y+2)-6=0

Short Answer

Expert verified

Solution for equation will be

  • y=0
  • y=-53

Step by step solution

01

Step 1.  Given Data

Quadratic Equation is(3y+2)2+(3y+2)-6=0

02

Step 2.  To Find  

We have to solve it and find the value of y.

03

Step 3.  Explanation

Let the value of(3y+2)=u

Then the equation is -

(3y+2)2+(3y+2)-6=0

Put the value of (3y+2)=u

role="math" localid="1645479510656" u2+u-6=0

(u-2)(u+3)=0

By using Zero product property -

u-2=0, u+3=0

u=2, u=-3

04

Step 4.  Calculation  

Replace u with (3y+2)

3y+2=2, 3y+2=-3

3y=2-2, 3y=-3-2

y=0, y=-53

There are two solutions -

  • y=0
  • y=-53

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