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Chapter 9: Q. 135 (page 898)

In the following exercises, solve by using the Quadratic Formula.
(y+4)(y-7)=18

Short Answer

Expert verified

The solutions of the given equation are y=32卤1932.

Step by step solution

01

Step 1. Write the quadratic equation in standard form.

The given equation is:

(y+4)(y-7)=18

The given equation can be written as:

y2-7y+4y-28=18y2-3y-28-18=0y2-3y-46=0

02

Step 2. Substitute the values in Quadratic Formula.

Quadratic Formula for the equation ax2+bx+c=0is:

x=-b卤b2-4ac2a

In the given equation, a=1,b=-3,c=-46. Substitute these values in Quadratic Formula.

y=-(-3)卤(-3)2-4(1)(-46)2(1)

03

Step 3. Simplify the value.

On simplification, we get

y=3卤9+1842y=3卤1932y=32卤1932

04

Step 4. Conclusion.

The solutions of the given equation are y=32卤1932.

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Most popular questions from this chapter

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