/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 492 5658... [FREE SOLUTION] | 91影视

91影视

Log out

Learning Materials

Features

Discover

Chapter 5: Q. 492 (page 564)

5658

Short Answer

Expert verified

The simplified form of the given expression is125.

Step by step solution

01

Step 1. Given information.

The given expression is:

5658

02

Step 2. Simplify the given expression.

The given expression can be written as:

5658=56-8鈭�aman=am-n=5-2=152鈭�a-n=1an=15脳5=125

03

Step 3. Conclusion.

The simplified form of the given expression is 125.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Find the product of the below expression.

t-92

In the following exercises, multiply the binomials. Use any method.

y-6y-2

Multiply each pair of conjugates using the product of the conjugates pattern.

15m2-8n415m2+8n4

Find the sum:14y2+6y-4+3y2+8y+5

Convert (a) 7.5脳106 (b) -4.13脳10-5 to decimal form.
See all solutions

Recommended explanations on Math Textbooks

Probability and Statistics

Read Explanation

Statistics

Read Explanation

Geometry

Read Explanation

Logic and Functions

Read Explanation

Applied Mathematics

Read Explanation

Calculus

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.