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Intermediate Algebra

OPENSTAX

$Math Studyset 91影视 Explanations$ Math

OER 2017 Edition 路 1346 pages

ISBN: 9780998625720

Chapter 5: Q. 311 (page 551)

Divide each polynomial by the binomial.
$(2 n^{3} - 10 n + 28) 梅 (n + 3)$

Short Answer

Expert verified

The solution is $(2 n^{2} - 6 n + 8 + \frac{4}{n + 3})$ .

Step by step solution

01

Step 1. Given information

Polynomial: $2 n^{3} - 10 n + 28$

Binomial: $n + 3$

02

Step 2. Calculation

Using long division -

$2 n^{2} - 6 n + 8 + \frac{4}{n + 3}$

role="math" localid="1645987521816" $n + 3 \overset{炉}{) 2 n^{3} - 10 n + 28}$

$2 n^{3} + 6 n^{2}$

role="math" localid="1645987672151" $\overset{炉}{- 6 n^{2} - 10 n + 28}$

$- 6 n^{2} - 18 n$

role="math" localid="1645987770440" $\overset{炉}{8 n + 28}$

$8 n + 24$

$\overset{炉}{4}$

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Write number (a) 1,290,000 (b) 0.00000103 in scientific notation

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