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Chapter 3: Q.476 (page 358)

In the following exercises, find an equation of a line perpendicular to the given line and contains the given point. Write the equation in slope鈥搃ntercept form.

line y = 3, point (鈭�1, 鈭�3)

Short Answer

Expert verified

Equation of the perpendicular line to y = 3 and passing though the point (-1, -3) is x = -1.

Step by step solution

01

Step 1. Given information

We have given equation of the line is y = 3 and point is (-1, -3).

02

Step 2. Concept

The line that is perpendicular to y = c is a horizontal line, because horizontal and vertical lines are perpendicular.

03

Step 3. Explanation

Here we have given equation of the line is

y = 3 which is horizontal line.

Also we know that vertical lines and horizontal lines are perpendicular to each other.

So the vertical line passing though the point (-1, 3) is x = -1 which is perpendicular to y = 3.

04

Step 4. Conclusion

Hence, equation of the perpendicular line to y = 3 and passing though the point (-1, -3) is x = -1.

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Most popular questions from this chapter

Find the equation of the line shown in each graph and write the equation in slope-intercept form.

Graph the equations

(a) x=5

(b)y=-4

Graph:f(x)=x2

Use graph of y=3x-1. For each ordered pair, decide :

(a) Is the ordered pair A(3,-1)B(-1,-4)a solution to the equation.

(b) Is the point A(3,-1)B(-1,-4)on the line?

Graph the equationsx=-2,y=-5.
See all solutions

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