91影视

$2x+3y>2$

$鈬�y>\frac{-2}{3}x+\frac{2}{3}$

To check whether $(1,1)$is a solution to the equation

Replace the values of x and y in $2x+3y>2$

Here $x=1,y=1$

$$\begin{gathered} 1>\frac{-2}{3}+\frac{2}{3} \\ 1>0 \end{gathered}$$

The point$(1,1)$is a solution

$2x+3y>2$

$鈬�y>\frac{-2}{3}x+\frac{2}{3}$

To check whether $(4,-3)$is a solution .

Replace the values of x and y in $2x+3y>2$$2x+3y>2$

Here $x=4,y=-3$

$$\begin{gathered} -3>\frac{-2}{3}脳4+\frac{2}{3} \\ -3>\frac{-8}{3}+\frac{2}{3} \\ -3鈮�-2 \end{gathered}$$

$$\begin{gathered} -3>\frac{-2脳4}{3}+\frac{2}{3} \\ -3>\frac{-8}{3}+\frac{2}{3} \\ -3>\frac{-6}{3} \\ -3鈮�-2 \end{gathered}$$

The point $(4,-3)$is not a solution

$2x+3y>2$

$鈬�y>\frac{-2}{3}x+\frac{2}{3}$

To check whether $(0,0)$is a solution

Replace the value of x and y in $2x+3y>2$

Here $x=0,y=0$

$$\begin{gathered} 0>\frac{-2}{3}脳0+\frac{2}{3} \\ 0鈮�\frac{2}{3} \end{gathered}$$

The point$(0,0)$is not a solution

$2x+3y>2$

$鈬�y>\frac{-2}{3}x+\frac{2}{3}$

To check whether $(-8,12)$is a solution to the equation

Replace the values of x and y in $2x+3y>2$

Here $x=-8,y=12$

$$\begin{gathered} 12>\frac{-2}{3}脳(-8)+\frac{2}{3} \\ 12>\frac{-14}{3} \end{gathered}$$

The point$(-8,12)$is a solution

$2x+3y>2$

$鈬�y>\frac{-2}{3}x+\frac{2}{3}$

Replace the value of x and y in $2x+3y>2$

Here $x=3,y=0$

$$\begin{gathered} 0>\frac{-2}{3}脳3+\frac{2}{3} \\ 0>-2+\frac{2}{3} \\ 0>\frac{-4}{3} \end{gathered}$$

The point$(3,0)$is a solution