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Find the equation of the line having the slope m=16and containing the point (6,1). Write the equation in the slope-intercept form.

Short Answer

Expert verified

The slope-intercept form of the line having the slope 16and the point (6,1)isy=16x

Step by step solution

01

Step 1. Given information

The slope of the line is m=16

The point on the line is (6,1)

To find the equation of the line in the slope-intercept form, we will make use of the slope-point formula.

02

Step 2. Formula

  • The slope-intercept form of a line is y=mx+bwhere mis the slope and bis the y-intercept.
  • The slope-point form of an equation of a line having the slopemand pointx1,y1isy-y1=m(x-x1)
03

Step 3. Equation of the line in slope-intercept form

The slope is m=16and the point is role="math" localid="1644481040865" (x1,y1)=(6,1)

Using the slope-point formula, we have

y-y1=m(x-x1)y-1=16(x-6)(∵x1=6,y1=1)y-1=16x-1y=16x-1+1y=16x

Therefore, the slope-intercept form of the equation of the line isy=16x

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