91Ó°ÊÓ

The boundary line shown in the graph is,

$x+y=5$

The line $x+y=5$is the boundary line.

On one side of the line are the points with $x+y>5$, and on the other side of the line are the points with $x+y<5$.

Let's test the point $(0,0)$and see which inequality describes its position relative to the boundary line.

At $(0,0)$which inequality is true: $x+y>5$or $x+y<5$

Checking if $x+y>5$, at $x=0,y=0$,

$$\begin{gathered} x+y>5 \\ ⇒0+0>5 \\ ⇒0>5 \end{gathered}$$

which is false.

Now, checking if $x+y<5$, at $x=0,y=0$,

$$\begin{gathered} x+y<5 \\ ⇒0+0<5 \\ ⇒0<5 \end{gathered}$$

which is true.

Since, $x+y<5$is true, the side of the line with $(0,0)$is the solution. The shaded region shows the solution of the inequality $x+y<5$.

Since, the boundary line is graphed with a solid line, the inequality includes the equal sign.

The graph shows the inequality$x+y≤5$