91Ó°ÊÓ

The equation of the given line is $y-1=0$and the point on the perpendicular line is $(-2,6)$.

We have to find the equation of the perpendicular line in slope-intercept form.

The given line is $y-1=0$

Rewriting this equation, we have $y=1$.

Note that $y=1$is the equation of a horizontal line. Therefore the line perpendicular to this must be a vertical line which passes through the point $(-2,6)$.

The equation of the vertical line is of the form $x=k$.

Since the perpendicular line passes through the point $(-2,6)$, every point on the line must have $-2$as the x-coordinate.

Therefore the equation of the perpendicular line is$x=-2$.

The equation of the line perpendicular to the line$y-1=0$and containing the point$(-2,6)$in slope-intercept form is$x=-2$.