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Chapter 1: Q 1.58. (page 48)

Simplify:

(a) 4k5鈭�16

(b)4k5路16

Short Answer

Expert verified

Part (a) The obtained value is 24k鈭�530.

Part (b) The obtained value is 2k15.

Step by step solution

01

Part (a) Step 1. Find the LCD of the denominator.

Consider the given expression.

4k5鈭�16

Find the factor of 5 and 6.

localid="1644662914052" 5=1路56=2路3LCD=2路3路5炉=30

02

Part (a) Step 2. Rewrite the expression.

Write the fraction as an equivalent fraction LCD.


4k5鈭�16=4k鈰�65鈰�6鈭�1鈰�56鈰�5=24k30鈭�530

Subtract the numerators and place the difference over the common denominators.

24k30鈭�530=24k鈭�530

03

Part (b) Step 1. Multiply the fractions.

Since the given operation is multiplication. Thus,

4k5鈰�16=4k鈰�15鈰�6

04

Part (b) Step 2. Cancel the common factors.

Factor the number and cancel the common factor from numerators and denominators.

4k鈰�15鈰�6=2鈰�2k5鈰�2鈰�3=2k5鈰�3=2k15

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