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Chapter 1: Q 1.41. (page 34)

Evaluate: 3x2鈭�2xy+6y2 when x=1,y=鈭�2.

Short Answer

Expert verified

The value is 31.

Step by step solution

01

Step 1. Given Information: 

The given expression is 3x2-2xy+6y2and the values of the variables are x=1and y=-2.

02

Step 2. Substitute the values: 

Substitute 1 for xand -2for yinto the given expression 3x2-2xy+6y2.

312-21-2+6-22

03

Step 3. Calculate the exponents:

The value of the exponents are 12=1and -22=4. Simplify the exponents in the obtained expression.

3路1-21-2+6路4

04

Step 4. Multiply: 

Perform multiplication from left to right.

3--4+24

05

Step 5. Perform Subtraction:

Subtract -4from 3 in the obtained expression.

7+24

06

Step 6. Perform Addition:

Add 7 and 24 in the obtained expression.

7+24=31

07

Step 7. Conclusion:

The required value is 31.

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Most popular questions from this chapter

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