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Intermediate Algebra

OPENSTAX

$Math Studyset 91影视 Explanations$ Math

OER 2017 Edition 路 1346 pages

ISBN: 9780998625720

Chapter 6: Q. 6.76 (page 609)

Factor completely: $27 x y^{3} + 48 x y$

Short Answer

Expert verified

The required factors are $3 x y (9 y^{2} + 16)$

Step by step solution

01

Step 1. Given Information

The given expression is $27 x y^{3} + 48 x y$

02

Step 2. Calculation

We will factor the expression by taking the common factor outside the paranthesis.

$27 x y^{3} + 48 x y = 3 x y (9 y^{2} + 16)$

03

Step 3. Check

We will verify the obtained factors by multiplying them.

3 x y (9 y^{2} + 16) = 27 x y^{3} + 48 x y

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Most popular questions from this chapter

In the following exercises, factor completely using the sums and differences of cubes pattern, if possible.

$27 y^{3} + 8 z^{3}$

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Factor by Grouping In the following exercises, factor by grouping.

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