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Chapter 6: Q. 437 (page 636)

For the function, f(x)=x2+11x+20, (a) find

when f(x)=鈭�8.(b) Use this information to find two

points that lie on the graph of the function.

Short Answer

Expert verified

(a) The xvalues for f(x)=-8are x=-7,-4

(b) Two points that lie on the graph of function are(-7,-8),(-4,-8)

Step by step solution

01

Step 1. Given

The function is f(x)=x2+11x+20

(a) We have to find when f(x)=-8

(b) We also have to find two points that lie on the graph of the function.

02

Step 2. Find values of x when f(x)=-8

f(x)=x2+11x+20-8=x2+11x+20x2+11x+28=0x2+7x+4x+28=0x(x+7)+4(x+7)=0(x+7)(x+4)=0

So,

x=-7,-4

03

Step 3. Check the value of f(x) at x=-7,-4

Substitute x=-7in f(x),

data-custom-editor="chemistry" f(x)=x2+11x+20f(-7)=(-7)2+11(-7)+20f(-7)=49-77+20f(-7)=-8

Substitute x=-4in f(x)

f(x)=x2+11x+20f(-4)=(-4)2+11(-4)+20f(-4)=16-44+20f(-4)=-8

04

Step 4. Find two points that lie on the graph of the function. 

Since, f(-7)=-8and f(-4)=-8, so the points (-7,-8)and (-4,-8) lie on the graph of the function.

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