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In the following exercise, factor completely using the perfect square trinomials pattern.

36a2−84ab+49b2

Short Answer

Expert verified

The factorisation of the given polynomial is:

36a2−84ab+49b2=(6a-7b)2

Step by step solution

01

Step 1. Given information 

The given polynomial is:

36a2−84ab+49b2

02

Step 2. Factorise the polynomial 

We know that,

a-b2=a2-2ab+b2

For polynomial 36a2−84ab+49b2we have:

36a2−84ab+49b2(6a)2-2×6a×7b+7b2[Using(a-b)2=a2-2ab+b2]6a-7b2

Thus, the factorisation of the given polynomial is:

localid="1644655841881" 36a2-84ab+49b2=(6a-7b)2

03

Step 3. check the answer

Multiplying the factors, we get:

36a2-84ab+49b2=(6a-7b)236a2-84ab+49b2=6a-7b)(6a-7b36a2-84ab+49b2=36a2-84ab+49b2

This is true.

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