/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 371 Factor Trinomials of the Form ax... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

Factor Trinomials of the Form ax2+bx+cUsing Trial and Error
In the following exercises, factor completely using trial and error.

-9a2+153a+18

Short Answer

Expert verified

By factoring the polynomial -81a2+153a+18completely by trial and error method, the factors are -9(9a+1)(a-2)

Step by step solution

01

Step 1. Given

The polynomial is -81a2+153a+18

To factor the polynomial by trial and error method.

02

Step 2. Factor any GCF

Factor the GCF
-81a2+153a+18=-9(9a2-19a-2)

03

Step 3. Find all the pairs of factors of first term

The factors of the first term are 1,9and 3,3

9a2-19a-2=(x)(9x)

9a2-19a-2=(3x)(3x)

04

Step 4. Find all the factor pairs of third term

Consider the sign.

Since the last term is -2, the factors have opposite sign.

Since the sign of the second term is negative, the greater factor have negative sign.

The factors of -2are

  • 1,-2
05

Step 5. Test all combination of factors

Test all combination of factors until the correct product is found.

Possible factors
Product
(9a-2)(a+1)
9a2+7a-2
(9a+1)(a-2)
9a2-17a-2
(3a-2)(3a+1)
9a2-3a-2
(3a+1)(3a-2)
9a2+3a-2

The factors are (9a+1)(a-2)

06

Step 6. Check the answer

Check by multiplying the factor.

-9(9a+1)(a-2)=-9(9a2-18a+a-2)

=-9a(9a2-17a-2)

=-81a2+153a+18

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.