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91Ó°ÊÓ

In the following exercises, use properties of logarithms to write each logarithm as a sum of logarithms. Simplify if possible.

log58a2b6cd3.

Short Answer

Expert verified

The solution is3log5(2)+2log5(a)+6log5(b)+log5(c)-3log5(d).

Step by step solution

01

Step 1. Given and explanation. 

We have log58a2b6cd3.

The product property states that if there is an expression as loga(m·n), it is equal to logam+logan.

The quotient property states that if there is an expression as logamn, it is equal to logam-logan.

Applying these properties, we get the solution.

02

Step 2. Expanding using quotient property.

We have log58a2b6cd3.

Using the quotient property, we can write this as ,

log5(8a2b6c)-log5(d3).

03

Step 3. Expanding using product property.

We have log5(8a2b6c)-log5(d3).

Using the product rule, we get
=log5(8a2b6c)-log5(d3)=(log58)+(log5a2)+(log5b6)+(log5c)-log5(d3)=log5(2)3+log5(a)2+log5(b)6+log5c-log5(d)3 =3log5(2)+2log5(a)+6log5(b)+log5(c)-3log5(d)
Thus we get the value.

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