/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 303 In the following exercises, solv... [FREE SOLUTION] | 91影视

91影视

In the following exercises, solve for x

log5(x+1)+log5(x-5)=log57

Short Answer

Expert verified

By solving the equation log5(x+1)+log5(x-5)=log57, the value of xis 6

Step by step solution

01

Step 1. Given

An expressionlog5(x+1)+log5(x-5)=log57

To solve the expression forx

02

Step 2. Use the Product property

By Product Property of logarithm

logaM+logaN=logaMN

log5((x+1)(x-5))=log57log5(x2-4x-5)=log57

03

Step 3. Use One to One property

If logaM=logaN, then M=N

x2-4x-5=7x2-4x-12=0

04

Step 4. Solve the equation

x2-4x-12=0(x-6)(x+2)=0x=-2,6

Logarithm for a negative number does not exist.

So,x=6

05

Step 5. Check the solution

Substitute x=6in the original equation and solve.

log5(6+1)+log5(6-5)=log57log5(7)+log5(1)=log57log57=log57

Hence the solution is checked.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91影视!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.