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Intermediate Algebra

OPENSTAX

$Math Studyset 91影视 Explanations$ Math

OER 2017 Edition 路 1346 pages

ISBN: 9780998625720

Chapter 10: Q. 135 (page 1033)

Convert from exponential to logarithmic form:
$17^{x} = \sqrt[5]{17}$ .

Short Answer

Expert verified

The logarithmic form is,

$x = \log_{17} (\sqrt[5]{17})$ .

Step by step solution

01

Step 1. Given the information.

The exponential form is,

$17^{x} = \sqrt[5]{17}$ .

02

Step 2. Changing to logarithmic form.

$17^{x} = \sqrt[5]{17} y = \log_{a} (x) x = \log_{17} (\sqrt[5]{17})$

If $17^{x} = \sqrt[5]{17}$ ,

then $x = \log_{17} (\sqrt[5]{17})$ .

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