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In the following exercises, graph each equation.

y2-x2-4y+2x-6=0

Short Answer

Expert verified

Equation given in the question represents a hyperbola.

Step by step solution

01

Identification of the conic

Given equation of the conic is,

y2-x2-4y+2x-6=0

Since, coefficients have the different signs, it's a hyperbola.

02

Convert the equation of the hyperbola in the standard form

y2-x2+2x-4y-6=0

(y2-4y+4)-(x2-2x+1)-3-6=0

(y-2)2-(x-1)2=9

(y-2)232-(x-1)232=1

03

Transverse axis and center of the hyperbola

Since, y2term of the equation is positive, transverse axis will be vertical.

Center of the hyperbola →(1,2)

04

Graph of the hyperbola will be,

a2=b2=9a=b=±3

Draw a rectangle that passes through the points 3units above and below the center and 3units left and right to the center.

Sketch the asymptotes - lines through the diagonals of the rectangle.

05

Graph the branches and mark the vertices.

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