/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 386 In the following exercise, facto... [FREE SOLUTION] | 91Ó°ÊÓ

91Ó°ÊÓ

In the following exercise, factor completely using the perfect square trinomials pattern.

5k3−70k2+245k

Short Answer

Expert verified

The factorisation of the polynomial is

5k3−70k2+245k=5k(k-7)2

Step by step solution

01

Step 1. Given information 

The given polynomial is:

5k2−70k2+245k

02

Step 2. Factorise the polynomial  

We know that,

(a-b)2=a2-2ab+b2

For the polynomial 5k3−70k2+245k, taking out 5kas a common, we get:

5k(k2-14k+49)

Now,

localid="1644658099435" 5k[k2-14k+49]5k[(k)2-2×k×7+72]5k(k-7)2[using(a-b)2=a2-2ab+b2]

Thus, the factorisation of the polynomial is:

localid="1644657063485" 5k3−70k2+245k=5k(k-7)2

03

Step 3. check the answer

Multiplying the factors, we get:

5k3−70k2+245k=5k(k-7)25k3−70k2+245k=5k(k2-14k+49)5k3−70k2+245k=5k3−70k2+245k

This is true.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with 91Ó°ÊÓ!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.