/*! This file is auto-generated */ .wp-block-button__link{color:#fff;background-color:#32373c;border-radius:9999px;box-shadow:none;text-decoration:none;padding:calc(.667em + 2px) calc(1.333em + 2px);font-size:1.125em}.wp-block-file__button{background:#32373c;color:#fff;text-decoration:none} Q. 346 Solve the nonlinear system of eq... [FREE SOLUTION] | 91Ó°ÊÓ

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Solve the nonlinear system of equations using substitution:

x2+y2=8y=-x-4

Short Answer

Expert verified

The type of graph for the given equations are circle and line.

Step by step solution

01

Step 1. Given Information

Given that the equation isx2+y2=8y=-x-4.

02

Step 2. Form of the equation

In the first equation, there is same coefficient of x2andy2.When a linear equation have two variable and it is line. The solution of x2+y2=8is circle and y=-x-4is line. On comparing the equation with the standard form,

(x-0)2+(y-0)2=22 h=0,k=0y=-x-4m=-1,b=-4(h,k)=(0,0)

The standard form ofx2+y2=8is(x-0)2+(y-0)2=22andy=-x-4isy=-x-4.

03

Step 3. Graph

On drawing the graph,

04

Step 4. Solution

The circle and line intersected at (-2,2) . On verifying the point in the equation by substitution,

x2+y2=8(-2)2+(-2)2=8 8=8y=-2x-1-2=-2(-2)-4-2=-2

It satisfies both the equation. Hence, the solution is (-2,2).

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