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Chapter 11: Q. 333 (page 1160)

a) Identify the type of graph of each equation as a circle, parabola, ellipse, or hyperbola, and b) Graph the equation.

4x2+49y2=196.

Short Answer

Expert verified

The equation shows the graph as ellipse.

Step by step solution

01

Step 1. Given Information

Given that the equation is4x2+49y2=196.

02

Step 2. Identification of equation

In the equation, squared terms coefficient are different and it is positive sign. Thus, the graph would be an ellipse.

03

Step 3. Standard form

On converting it into standard form,

4x24+49y24=1964x2+49y24=49x249+y24=1(x-0)272+(y-0)222=1

The centre of ellipse is (0,0).

The length of the major axis is 7 units.

The length of minor axis is 2 units.

04

Step 4. Graph of the equation

On graphing the given equation,

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