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In the following exercises, solve the system of equations by using elimination.

x2-y2=5-2x2-3y2=-30

Short Answer

Expert verified

Solution

x=3, y=2x=-3, y=2x=3, y=-2x=-3, y=-2(3,2)(-3,2)(3,-2)(-3,-2)

Step by step solution

01

Given Information 

Given equations are

x2-y2=5-2x2-3y2=-30

02

Eliminate a variable 'x'

x2-y2=5-2x2-3y2=-30Multiplythefirstequationby22x2-2y2=10-2x2-3y2=-30--------------5y2=-20y2=4y=±2

03

solve for x

we got y= +2, y=-2

Substitute it in any one of the equation and solve for x

x2-y2=5y=+2x2-22=5x2-4=5x2=9x=±3(2,3)and(2,-3)x2-y2=5y=-2x2-(-2)2=5x2-4=5x2=9x=±3(-2,3)and(-2,-3)

04

verify the solution 

(3,2)x2-y2=5(3)2-(2)2=5,True-2x2-3y2=-30-2(3)2-3(2)2=-30,true(-3,2)x2-y2=5(-3)2-(2)2=5,True-2x2-3y2=-30-2(-3)2-3(2)2=-30,true(3,-2)x2-y2=5(3)2-(-2)2=5,True-2x2-3y2=-30-2(3)2-3(-2)2=-30,true(-3,-2)x2-y2=5(-3)2-(-2)2=5,True-2x2-3y2=-30-2(-3)2-3(-2)2=-30,true

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